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Question 36 (Choice 2) Evaluate the product AB, where A = 8(1&−1&0@2&3&4@0&1&2) and B = 8(2&2&−4@−4&2&−4@2&−1&5) Hence the solve system of linear equations x – y = 3 2x 3y 4z = 17 y 2z = 7 Finding the product 8(1&−1&0@2&3&4@0&1&2) 8(2&2&−4@−4&2&−4@2&−1&5) = 8(1(2)(⤶7−1)(−4)X^2 2 y^2 = 1 Natural Language;Add '3y' to each side of the equation 2x 3y 3y = 0 3y Combine like terms 3y 3y = 0 2x 0 = 0 3y 2x = 0 3y Remove the zero 2x = 3y Divide each side by '2' x = 15y Simplifying x = 15y Subproblem 2
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Steps for Solving Linear Equation y=2x1 y = 2 x − 1 Swap sides so that all variable terms are on the left hand side Swap sides so that all variable terms are on the left hand side 2x1=y 2 x − 1 = y Add 1 to both sides Add 1 to both sidesSimplify (2x3y)^2 Rewrite as Expand using the FOIL Method Tap for more steps Apply the distributive property Apply the distributive property Apply the distributive property Simplify and combine like terms Tap for more steps Simplify each term Tap for more steps Multiply byEncuentra una respuesta a tu pregunta 3(2x6)(x(3x8)2)1=2(32x)ayudaa plis si no me he equivocado y creo que no (por que esto es una de las cosas que mejor se me dan y más me gustan) esto no es una ecuación
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Transcript Ex 33, 2 Solve 2x 3y = 11 and 2x – 4y = – 24 and hence find the value of 'm' for which y = mx 3 2x 3y = 11 2x – 4y = –24 From (1) 2x 3y = 11 2x = 11 – 3y x = (𝟏𝟏 − 𝟑𝒚)/𝟐 Substituting value of x in (2) 2x – 4y = – 24 2 ((11 − 3𝑦)/2)−4𝑦 = – 24 11 – 3y – 4y = – 24 11 – 7y = – 24 –7y = – 24 – 11 –7y = – 35 yExtended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, musicIntegrate x^2 sin y dx dy, x=0 to 1, y=0 to pi;
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Graph y=2/3x2 Rewrite in slopeintercept form Tap for more steps The slopeintercept form is , where is the slope and is the yintercept Write in form Tap for more steps Reorder terms Remove parentheses Use the slopeintercept form to find the slope and yinterceptExpress the following equations in matrix form and solve them by method of reductionx y z = 1, 2x 3y 2z = 2 and x y 2z = 4 Maharashtra State Board HSC Commerce 12th Board Exam Question Papers 195 Textbook Solutions Online Tests 99 Important Solutions 24700 votes 1 answer
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Answer (1 of 3) Let us break the expression and write the terms separately (2x^2–4x)(3y^2–12y)18 take the common values out 2×(x^2–2x)3×(y^2–4y)18 to make them perfect values we must add & subtract the constantsThe following expression can be written as {2×(x^2–2x1)}2{3×(y^2–4y4) At the end of the year 16, the population of villages Kovad, Varud, Chikhali is 5x 2 – 3y 2, 7y 2 2xy and 9x 2 4xy respectively At the beginning of the year 17, x 2 xy – y 2 , 5xy and 3x 2 xy persons from each of the three villages respectively went to another village for education, then what is the remaining total populationThe number x is 2 more than the number y If the sum of the squares of x and y is 34, then find the product of x and y Solution 15 Given x is 2 more than y, so x = y 2 If 2x 3y = 10 and xy = 16;
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Simplify (3x2y)^2 (2x3y)^2 \square!Solve the Following Simultaneous Equations 2 X 2 3 Y = 1 6 ;See the entire solution process below Explanation Step 1) Solve the first equation for x 2x 3y = 16 2x 3y −(3y)= 16−(3y) More Items 2x=13y Subtract 3y from both sides \frac {2x} {2}=\frac {13y} {2} Divide both sides by 2 x=\frac {13y} {2} Dividing by 2 undoes the multiplication by 2 3y=12x
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Answer2 (i) 21 py 2 – 56py = 7py (3y – 8) (ii) 4x 3 – 6x 2 = 2x 2 (2x – 3) Question 3 (i) 25abc 2 – 15a 2 b 2 c (ii) x 2 yz xy 2 z xyz 2 Answer3 (i) 25abc 2 – 15a 2 b 2 c = 5abc (5c – 3ab) (ii) x 2 yz xy 2 z xyz 2 = xyz(x y z) Question 4 (i) 8x 3 – 6x 2 10x (ii) 14mn 22m – 62p Answer4 (i) 8x 3 – 6x 2 10x = 2x (4x 2 – 3x 5) (ii) 14mn 22mSolve the following simultaneous equations using Cramer's rule2x 3y = 2; can you please explain how to to find dy/dx for the function x^2 y Y^2 x = 2 asked in CALCULUS by mathgirl Apprentice differentiation;
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Answer (1 of 4) You can solve this question easily Just try to eliminate all the constant Remember Maximum number of times you can do derivative is equal to the number of constants present Here it's 2 First try to solve it by yourself then look at the solution below Hope it's at par youProve that the Lines 2x − 3y 1 = 0, X Y = 3, 2x − 3y = 2 and X Y = 4 Form a Parallelogram Department of PreUniversity Education, Karnataka PUC Karnataka Science Class 11 Textbook Solutions 9263 Important Solutions 3 Question Bank Solutions 53 Concept Notes & Videos 581Answer (1 of 3) The point of intersection in the lines of 2x3y=10 and 3x2y=5 is \left(\frac{10×2–3×5}{2×2–3×3}, \frac{2×510×3}{2×2–3×3}\right) which is \left(1, 4\right) The intersection of axby=c and dxey=f is \left(\frac{c×eb×f}{a×eb×d}, \frac{a×fc×d}{a×eb×d}\right) where the li
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