For example 1/2 and 2/4 are equivalent, y/(y1) 2 and (y 2 y)/(y1) 3 are equivalent as well To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective MultiplierLet us Take is (x1)/22/(x1)=(x1)/33/(x1)5/6 I hope ur real number are one site and other site is x by numerical (X1)/2(x1)/35/6=3/(x1)2/(x1) Take both Respuesta x=2 Explicación paso a paso2x23x6=5x51x8=5x4x5x=486x=12X= 6/12X=2 dania está esperando tu ayuda Añade tu respuesta y gana puntos

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5/x-1 1/y-2=2 6/x-1-3/y-2=1
5/x-1 1/y-2=2 6/x-1-3/y-2=1-You can put this solution on YOUR website!SOLUTION 1 Begin with x3 y3 = 4 Differentiate both sides of the equation, getting (Remember to use the chain rule on D ( y3 ) ) so that (Now solve for y ' ) Click HERE to return to the list of problems SOLUTION 2 Begin with ( x y) 2 = x y 1 Differentiate both




5 X 1 1 Y 2 2 6 X 1 3 Y 2 1
y=2(x5)^22 is a continuous function with an infinite number of (x,y) pairs which could be considered solutions There is no "solution" graph{2(x5)^22 14, 6, 908, 092} We could find the solutions for a couple of points that are often of interest The equation itself is in the "vertex form" and we can read the coordinates of the vertex directly from the equation (5,2) Ex 32, 11 If x 8(2@3) y 8(−1@1) = 8(10@5) , find values of x and y x 8(2@3) y 8(−1@1) = 8(10@5) 8(2𝑥@3𝑥) 8(−𝑦@𝑦Math Input NEW Use textbook math notation to enter your math Try it
Solve for x 5/21/3=1/x Rewrite the equation as Factor each term Tap for more steps To write as a fraction with a common denominator, multiply by To write as a fraction with a common denominator, multiply by Write each expression with a common denominator of , by multiplying each by an appropriate factor ofAs before, I'll set these equations equal, and solve for the values of x 2x 2 3x 4 = x 2 2x 3 x 2 x 1 = 0 Using the Quadratic Formula But I can't graph that negative inside the square root!Simple and best practice solution for Y1=5(x2) equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand,
Math Input NEW Use textbook math notation to enter your math Try it Transcript Ex 72 , 6 If (1, 2), (4, y), (x, 6) and (3, 5) are the vertices of a parallelogram taken in order, find x and y Let the points be A(1, 2), B(4, y), C(x, 6), D(3, 5) We know that diagonals of parallelogram bisect each other So, O is the mid−pint of AC & BD Finding mid−point of AC We have to find co−ordinates of O x−coordinate of O = (𝑥1 𝑥2)/2 y−coordinateWe get their width by subtracting the xcoordinate of the edge on the left curve from the xcoordinate of the edge on




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Simple and best practice solution for Y(2)=3(x5) equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the equation solver your own equation and let us solve itGraph y=(x1)^25 Find the properties of the given parabola Tap for more steps Use the vertex form, , to determine the values of , , and The directrix of a parabola is the horizontal line found by subtracting from the ycoordinate of the vertex if the parabola opens up or downY=3 (x5) (x2) Simple and best practice solution for y=3 (x5) (x2) equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the equation solver your own equation and let us solve it




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X^2(y(x^2)^(1/3))^2 = 1 Natural Language;PreAlgebra Graph y5=1/5* (x2) y − 5 = 1 5 ⋅ (x − 2) y 5 = 1 5 ⋅ ( x 2) Move all terms not containing y y to the right side of the equation Tap for more steps Add 5 5 to both sides of the equation y = x 5 − 2 5 5 y = x 5 2 5 5 To write 5 5 as a fraction with a common denominator, multiply by 5 5 5 5Then add the square of 1 to both sides of the equation This step makes the left hand side of the equation a perfect square x^ {2}2x1=4 Add 3 to 1 \left (x1\right)^ {2}=4 Factor x^ {2}2x1 In general, when x^ {2}bxc is a perfect square, it can always be factored as \left (x\frac {b} {2}\right)^ {2}




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Solve for x and y 3/x 6/y = 7, 9/x 3/y = 11 asked Jun 23 in Linear Equations by Hailley (334k points) linear equations in two variables;For example 1/2 and 2/4 are equivalent, y/(y1) 2 and (y 2 y)/(y1) 3 are equivalent as well To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective MultiplierSimple and best practice solution for (2/3)x1=5 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand,



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We can find the arc length to be 1261 240 by the integral L = ∫ 2 1 √1 ( dy dx)2 dx Let us look at some details By taking the derivative, dy dx = 5x4 6 − 3 10x4 So, the integrand looks like √1 ( dy dx)2 = √( 5x4 6)2 1 2 ( 3 10x4)2 by completing the squareSOLUTION 1 Begin with x3 y3 = 4 Differentiate both sides of the equation, getting (Remember to use the chain rule on D ( y3 ) ) so that (Now solve for y ' ) Click HERE to return to the list of problems SOLUTION 2 Begin with ( x y) 2 = x y 1 Differentiate bothClick here👆to get an answer to your question ️ If (1, 2), (4, y), (x, 6) and (3, 5) are the vertices of a parallelogram taken in order, find x and y



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I'll just solve #2 and #9 All are similar to these two 2 2xy=6xy=1 Substitution method Pick one of the unknowns and an equation that contains it21 Subtracting a fraction from a whole Rewrite the whole as a fraction using 5 as the denominator x x • 5 x = —— = —————— 1 5 Equivalent fraction The fraction thus generated looks different but has the same value as the whole Common denominator The equivalent fraction and the other fraction involved in the The area is 32/3 Start by finding the intersection points {(y = x^2 2x 1), (y= 2x 5)} Substitute the second equation into the first 2x 5 = x^2 2x 1 0 = x^2 2x 2x 1 5 0 = x^2 4 0 = (x 2)(x 2) x = 2 and 2 y = 2x 5 y = 2(2) 5 and y = 2(2) 5 y = 1 and y = 9 The solution set is hence {2, 1} and {2, 9} The next step is doing a basic sketch of the graph This




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Solve for x 2/5*(x1)=g Multiply both sides of the equation by Simplify both sides of the equation Tap for more steps Simplify Tap for more steps Cancel the common factor of Tap for more steps Cancel the common factor Rewrite the expression Cancel the common factor ofFigure 3 The 2area between x = y and y = x − 2 and one horizontal rectangle The height of these rectangles is dy; Transcript Ex 36, 1 Solve the following pairs of equations by reducing them to a pair of linear equations (i) 1/2𝑥 1/3𝑦 = 2 1/3𝑥 1/2𝑦 = 13/6 1/2𝑥 1/3𝑦 = 2 1/3𝑥 1/2𝑦 = 13/6 Let 1/𝑥 = u 1/𝑦 = v So, our equations become 1/2 u 1/3 v = 2 (3𝑢 2𝑣)/(2 × 3) = 2 3u 2v = 12 1/3 u 1/2 v = 13/6 (2𝑢 3𝑣)/(2 × 3) = 13/6 2u 3v = 13 Our equations



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x = 2, y = 9 You have a simple system of linear equations and can use the substitution method So take one of the equations and solve for x We are going to use the second equation, because the coefficient of x is already 1 x 2/5y = 8/5 x = 8/5 2/5y Now let's substitute the x in our first equation 2/5x 1/5y = 1 2/5*(8/52/5y) 1/5y = 1 16/25 4/25y 1/5y = 1 1/25y = 9/25 y Ex 21, 1 If (x/3 " 1, y –" 2/3) = (5/3 "," 1/3) , find the values of x and y (x/3 " 1, y –" 2/3) = (5/3 "," 1/3) Since the ordered pairs are equal, corresponding elements are equal Hence x/3 1 = 5/3 x/3 = 5/3 – 1 x/3 = 2/3 x = 2 y – 2/3 = 1/3Equations Tiger Algebra gives you not only the answers, but also the complete step by step method for solving your equations 6=(152x)^2/(15x)^2 so that you understand better




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Simple and best practice solution for 5/6x2=1/x1 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, soX^2 2 y^2 = 1 Natural Language;About Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How works Test new features Press Copyright Contact us Creators




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Y = − 2 5x y = 2 5 x Use the slopeintercept form to find the slope and yintercept Tap for more steps Find the values of m m and b b using the form y = m x b y = m x b m = − 2 5 m = 2 5 b = 0 b = 0 The slope of the line is the value of m m, and the yintercept is the value of b b Slope − 2 5 2 5Tangents to the curve y = x3 − 3x2 −7x6 cut off on the negative semi axis OX a line segment half that on the positive semi axis OY is Let the point of tangency be (x_1,y_1) Then the equation of tangent is \displaystyle\frac {yy_1} {xx_1}=3x_1^26x_17 When y=0, \displaystyle x=x_1\frac {y_1} {3x_1^26x_17}Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!



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What is 2 1/6 x 3 2/5 2 1/6 * 3 2/5 = 13/6 * 17/5 = 221/30 Answer 7 11/30 obuong3@aolcomExtended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, musicD ( x 2/3 y 2/3) = D ( 8 ) , D ( x 2/3) D ( y 2/3) = D ( 8 ) , (Remember to use the chain rule on D ( y 2/3) ) (2/3)x1/3 (2/3)y1/3 y' = 0 , so that (Now solve for y' ) (2/3)y1/3 y' = (2/3)x1/3, , and , Since lines tangent to the graph will have slope $ 1 $ , set y' = 1 , getting , y 1/3 = x 1/3, y 1/3 = x 1/3, ( y 1/3) 3



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You can put this solution on YOUR website!Apply the distributive property by multiplying each term of 2 5 x 2 1 0 x 1 by each term of 2 x − 3 Combine 75x^ {2} and x^ {2} to get 55x^ {2} Combine − 7 5 x 2 and 2 0 x 2 to get − 5 5 x 2 Combine 30x and 2x to get 28x Combine − 3 0 x and 2 x to get − 2 8 xNotice that when x = 0 the value of y is 3/1 so this line "cuts" the y axis at y= yintercept = 3/1 = Calculate the XIntercept When y = 0 the value of x is 3/2 Our line therefore "cuts" the x axis at x= xintercept = 3/2 = Calculate the Slope Slope is defined as the change in y divided by the change in x



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Y=x3x212x No solutions found Rearrange Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation y(x^3x^212*x)=0Weekly Subscription $199 USD per week until cancelled Monthly Subscription $699 USD per month until cancelled Annual Subscription $2999 USD per year until cancelledUse the distributive property to multiply y by x 2 1 Add x to both sides Add x to both sides All equations of the form ax^ {2}bxc=0 can be solved using the quadratic formula \frac {b±\sqrt {b^ {2}4ac}} {2a} The quadratic formula gives two solutions,




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0 votes 1 answer Solve for x and y 10/xy 2/xy = 4 ,15/xy9/xy = 2,where x ≠ y, x ≠ y Solve for x and y 3/x 1/y 9 = 0 , 2/x 3/y = 5




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